n^2-61n+900=0

Solution for n^2-61n+900=0 equation:

n^2-61n+900=0

a = 1; b = -61; c = +900;
Δ = b2-4ac
Δ = -612-4·1·900
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{121}=11$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-61)-11}{2*1}=\frac{50}{2}
=25
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-61)+11}{2*1}=\frac{72}{2}
=36
$